Designer PDF Viewer - HackerRank.

When you select a contiguous block of text in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently. For example:

In this challenge, you will be given a list of letter heights in the alphabet and a string. Using the letter heights given, determine the area of the rectangle highlight in  assuming all letters are  wide.

For example, the highlighted . Assume the heights of the letters are  and . The tallest letter is  high and there are  letters. The hightlighted area will be  so the answer is .

Function Description

Complete the designerPdfViewer function in the editor below. It should return an integer representing the size of the highlighted area.

designerPdfViewer has the following parameter(s):

• h: an array of integers representing the heights of each letter
• word: a string

Input Format

The first line contains  space-separated integers describing the respective heights of each consecutive lowercase English letter, ascii[a-z].
The second line contains a single word, consisting of lowercase English alphabetic letters.

Constraints

• , where  is an English lowercase letter.
•  contains no more than  letters.

Output Format

Print a single integer denoting the area in  of highlighted rectangle when the given word is selected. Do not print units of measure.

Sample Input 0

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
abc

Sample Output 0

9

Explanation 0

We are highlighting the word abc:

Letter heights are ,  and . The tallest letter, b, is  high. The selection area for this word is .

Note: Recall that the width of each character is .

Sample Input 1

1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 7
zaba

Sample Output 1

28

Explanation 1

The tallest letter in  is  at . The selection area for this word is .

NOTE: If you are copying my code then its a advise to you to copy it after downloading it to avoid any kind of compilation error its link is available at the bottom of source code.

SOURCE CODE

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

// Complete the designerPdfViewer function below.

static int designerPdfViewer(int[] h, String word) {

int ar[]=new int[word.length()];

for(int i=0;i<word.length();i++)

{

char ch=word.charAt(i);

if(ch>='a'&&ch<='z')

{

ar[i]=(int)ch-97;

}

}

int max=0;

for(int i=0;i<ar.length;i++)

{

if(h[ar[i]]>max)

max=h[ar[i]];

}

return(max*word.length());

}

private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) throws IOException {

BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

int[] h = new int[26];

String[] hItems = scanner.nextLine().split(" ");

scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

for (int i = 0; i < 26; i++) {

int hItem = Integer.parseInt(hItems[i]);

h[i] = hItem;

}

String word = scanner.nextLine();

int result = designerPdfViewer(h, word);

bufferedWriter.write(String.valueOf(result));

bufferedWriter.newLine();

bufferedWriter.close();

scanner.close();

}

}

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OUTPUT

If you have any question then leave a comment below I will do my best to answer that question.